Pre-Calculus

posted by .

Please check:
1.Find polar equation of x^2 + y^2 = 10y
r^2 for x^2 + y^2 and sin(theta sin for y
=r^2=10sin(theta)
2. y=5
r=5/sin
3. x^2+y^2
=x^2 + y^2 =2x+3y

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. algebra

    Can someone please help me do this problem?
  2. Pre Cal

    sin theta - 2sin^2 theta = 0 I'm using the up carrot sign to signal "to the power of..." Let sin theta = x x - 2 x^2 = 0 x (1 - 2x) = 0 Both x=0 and x = 1/2 are solutions. theta = 0 degrees, 30 degrees, 150 degrees and 180 degrees. …
  3. Calculus

    I wanted to confirm that I solved these problems correctly (we had to convert the polar curves to Cartesian equations). 1.rcos(theta)=1 x=1 2.r=2*sin(theta)+2*cos(theta) r^2=2rsin(theta)+2rcos(theta) x^2+y^2=2y+2x (a little unsure …
  4. Pre-Calculus

    translate this polar equation into a rectangular form: rsin(2theta)=sin(theta) My answer: r2sin(theta)cos(theta)=sin(theta) 2rcos(theta)=1 2x=1 x=1/2 This is the only answer I can get and someone told me it's wrong. Would someone please …
  5. Algebra II

    Multiple Choice Which expression is NOT equivalent to 1?
  6. Pre-Calculus-Please check

    Please check: 1.Find polar equation of x^2 + y^2 = 10y subbed r^2 for x^2 + y^2 and sin(theta sin for y =r^2=10sin(theta) 2. y=5 r=5/sin 3. x^2+y^2 =x^2 + y^2 =2x+3y
  7. Pre-Calculus

    Please check: 1.Find polar equation of x^2 + y^2 = 10y r^2 for x^2 + y^2 and sin(theta sin for y =r^2=10sin(theta) 2.Find polar equation: y=5 r=5/sin 3.Polar equation is r=2costheta + 3 sin theta Find rectangular equation x^2+y^2 =x^2 …
  8. Pre-Calculus

    Sorry to be a pest but I never got an answer and I'm really stuck Can you please check this equation. Find polar equation of x^2 + y^2 = 10y x^2 + y^2 = r^2 r^2 = 10sin(theta)
  9. Polar Equations

    I am supposed to identify the classical curve that is represented by r = 1 + sin Theta. I think it's a cardioid, because its equation is r = 1 + 1 sin theta (r = a + a sin theta). Is this correct?
  10. Trigonometry

    Solve the equation for solutions in the interval 0<=theta<2pi Problem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1 3(cos^2/sin^2) - 4sin/sin^2 = 1 3cos^2 -4sin =sin^2 3cos^2-(1-cos^2) =4sin 4cos^2 -1 =4sin Cos^2 - sin=1/4 …

More Similar Questions