Calculus
posted by Linda
If any body can solve this I would be greatly appreciative. I spent an hour in the tutoring center and no one could solve. Here goes:
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed of 1.6 m/s, how fast is the length of his shadow on the building decreasing when he is 4 m from the building?

drwls
When he is 4 m from the building, he is 8 m from the spotlight. The length of his shadow on the building at that time is 3 m.
The length of his shadow on the building when he is x meters from the spotlight is
Y = 2*(12/x) = 24/x
dY/dt = (dY/dx)*(dx/dt) = (24/x^2)*1.6
= (24/64)*1.6 = 0.6 m/s
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