posted by Tina .
A mass of 11 kg is placed on a frictionless incline which is inclined at an angle of 69 degrees above the horizontal. It is held in place by a rope which is attached to a wall at the top of the incline. The rope is angled 13 degrees above the direction parallel to the incline, however. What is the normal force on the mass in Newtons?
W = mg = 11kg * 9.8N/kg = 107.8N. = weight of the mass.
Fm = (107.8N.,69deg.).
Fv = 107.8cos69 = 38.63N. = Force perpendicular to the incline = The normal force.