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A stone falls from a cliff. It lands on the ground below the cliff after 4.2 seconds. The height of the cliff can be calculated to be what?

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It will be the distance that an object falls in 4.2 s, with zero initial vertical velocity component.

You surely know the formula for that:

Y = (g/2) t^2

t = 4.2 s g = 9.8 m/s^2

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