Physics
posted by George .
An unmarked police car traveling a constant 80 is passed by a speeder traveling 145 .Precisely 2.50 after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 1.80 , how much time passes before the police car overtakes the speeder after the speeder passes (assumed moving at constant speed)?
I am getting t = 22.06, and its wrong :( Could someone help me out please!
Thanks

You need to provide dimensions with your numbers. That could be why you got the wrong answer.

Since Xf for the police is going to be equal to the Xf of the speeder we know that we can write two equations for the speeder and the police and set them equal to each other in order to solve for t.
first we need to convert
Police: v1=80km/hr>22.22m/s
Speeder: v2=145km/hr>40.27 m/s
Police: Xf= vt + (0.5)(a)t^2
Xf=22.22*t+(0.5)(1.8)(t2.5)^2
Speeder:
Xf=40.27*t
Solve for t by setting the eqns equal to each other
So we get:
0.9t^222.55t+5.63
use the quad. eqn to solve for t
t=24.8
Respond to this Question
Similar Questions

Physics.
An unmarked police car traveling a constant 95 km/h is passed by a speeder traveling 120 km/h. Precisely 1.00 sec. after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 1.90 m/s^2 … 
physics
An unmarked police car traveling a constant 90 km/h is passed by a speeder. Precisely 2.00 s after the speeder passes, the police officer steps on the accelerator. If the police car accelerates uniformly at 2.00 m/s^2 and overtakes … 
college physics 44
An unmarked police car traveling a constant 95km/h is passed by a speeder traveling 14km/h .Precisely 2.50s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 2.30m/s^2 , how … 
physics  college
An unmarked police car traveling a constant 95km/h is passed by a speeder traveling 14km/h .Precisely 2.50s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 2.30m/s^2 , how … 
physics  college
An unmarked police car traveling a constant 95km/h is passed by a speeder traveling 14km/h .Precisely 2.50s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 2.30m/s^2 , how … 
physics
An unmarked police car traveling a constant 95km/h is passed by a speeder traveling 14km/h .Precisely 2.50s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 2.30m/s^2 , how … 
Physics
An unmarked police car traveling a constant 80 km/h is passed by a speeder traveling 125 km/h. Precisely 3.00 s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 2.40 m/s^2, … 
Physics
An unmarked police car traveling a constant 80km/h is passed by a speeder traveling 135km/h. Precisely 3.00s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 1.50m/s^2 , how … 
Physics
An unmarked police car traveling a constant 85.0 km/h is passed by a speeder traveling 130 km/h . Precisely 3.00 s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 2.30 m/s2 … 
Physics
An unmarked police car traveling a constant 90 km/h is passed by a speeder traveling 128 km/h. Precisely 1.00 s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 2.80 m/s2 , …