Calculus
posted by Untamed .
About rationalizing denominator, is it true that you can't always multiply by the same square root denominator to get a perfect square?

Calculus 
Steve
yes, because (√n)² = n
so, multiplying the root by itself gets rid of the root.
If the denominator is not just a root, but something like √m + n, then you need to multiply by √m  n, since
(√m + n)(√m  n) = m  n²
also, you sometimes have to use
(√m + √n)(√m  √n) = m  n
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