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how do i find the derivative of 16^(sinx)

  • calc -

    y = 16^(sin x)
    ln y = sin x * ln 16

    1/y y' = ln 16 * cos(x)

    y' = ln 16 * cos x * 16^(sin x)

    In general, d/dx (e^u) = e^u du/dx

    d/dx (a^u) = ln a * a^u du/dx

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