algebra
posted by babygirl .
simplify
263*2/4^4+3^4
266/256+81
20/337
1252*5/3^3/3^2(3)^2
12510/27/9(9)
115/39
115/27
want to know if these two problem right

266/256+81
= 20/337 ????????
how in the world did you ever get that ???
266/256+81
= 107  6/256 = 107  3/128
= 106 125/128
or 13693/128
in 2nd, if you have consecutive division, do them in the order they come
125  2*5/3^3/3^2  (3)^2
= 125  10/27/9  9
= 125  10/243  9
= 116  10/243
= 115 233/243
or 28178/243 or 115.9588...
GOOGLE said http://www.google.com/search?hl=en&source=hp&biw=1643&bih=936&q=1252*5%2F3%5E3%2F3%5E2%283%29%5E2+&oq=1252*5%2F3%5E3%2F3%5E2%283%29%5E2+&aq=f&aqi=&aql=1&gs_sm=e&gs_upl=1511l1511l0l2589l1l1l0l0l0l0l272l272l21l1l0
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