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An automobile starts from rest and accelerates to a final velocity in two stages along a straight road. Each stage occupies the same amount of time. In stage 1, the magnitude of the car's acceleration is 2.03 m/s2. The magnitude of the car's velocity at the end of stage 2 is 4.87 times greater than it is at the end of stage 1. Find the magnitude of the acceleration in stage 2.

  • physics -

    Vf1 = Vo + at,
    Vf1 = 0 + 2.03t = 2.03t.

    Vf2 = 2.03t + 4.87*2.03t = 11.92t,
    Vf2 = at = 11.92t,
    at = 11.92t,
    Divide both sides by t:
    a = 11.92m/s^2=acceleration in stage 2.

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