trigonometry
posted by michael .
the height of a triangle is 10m longer than twice its base. its area is 176m^2. Find the lengths of its height and base.

base = x
height = 2x+10
(1/2)(x)(2x+10) = 176
2x^2 + 10x = 352
x^2 + 5x  176 = 0
(x + 16)(x11) = 0
x = 16 or x = 11 , but x > 0
so x = 11
base is 11, height is 32
check: (1/2)(11)(32) = 176
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