posted by bluedevil .
THe following reaction is carried out in a bomb calorimeter:
4NH3(g )+ 5O2(g) ---> 4NO(g) + 6H20
The calorimeter constant is 45.0kJ/K. WHen 34.0g of NH3 are reacted in the calorimeter, the temperature rises by 10.0C. What is the change in energy, dE (where d is delta), for the reaction?