the molar mass of CopperII Nitrate
CU(NO3)2 is _________grams
Ok so I
1. Cu= 63.55
2. N=14.01
3. 0= 6 X 16.00=96
I get 96.+14.01+63.55? =173.56
Answer is 188 grams? What did I do wrong?
Thank You
I got it myself:
Yeah!
63.55 + (14.01 + 48)x 2 = 187.55g/moles
187.55g/moles
To find the molar mass of Copper(II) Nitrate (Cu(NO3)2), you need to correctly calculate the atomic masses of each element and then add them together.
Here are the correct atomic masses for the elements:
- Cu (Copper) = 63.55 g/mol
- N (Nitrogen) = 14.01 g/mol
- O (Oxygen) = 16.00 g/mol
Now, let's calculate the molar mass:
1. Start with the Cu atom: 1 * 63.55 g/mol = 63.55 g/mol
2. Move to the N atom: 2 * 14.01 g/mol = 28.02 g/mol
3. Finally, the O atoms: 6 * 16.00 g/mol = 96.00 g/mol
Now, add up all the values:
63.55 g/mol + 28.02 g/mol + 96.00 g/mol = 187.57 g/mol
Therefore, the correct molar mass of Copper(II) Nitrate is approximately 187.57 grams per mole, not 188 grams.