Math

posted by .

Four couples have purchased ticket to the school play. Their sear are next to one another in a single row. If each couple sits side by side, how many seating arrangements are possible?

(I came up with 24. correct??)

  • Math -

    I count 64 posibilitys: p=person s=seat
    p ssssssss
    p ssssssss
    p ssssssss
    p ssssssss
    p ssssssss
    p ssssssss
    p ssssssss
    p ssssssss

  • Math -

    is that with the requirement that each couple sit side by side?

  • Math -

    no

  • Math -

    if the couples have to sit side by side then i count 32

  • Math -

    In the first seat: There are 8 possibilites for who sits there.

    In the second seat: There is only 1 possibility (the other member of the couple).

    In the third seat: There are 6 possibilites for who sits there.

    In the fourth seat: There is only 1 possibility (the other member of the couple).

    In the fifth seat: There are 4 possibilities for who sits there.

    In the sixth seat: There is only 1 possibility (the other member of the couple).

    In the seventh seat: There are 2 possibilities for who sits there.

    In the eighth seat: There is only 1 possibility (the last member of the last couple).

    Answer: 8*1*6*1*4*1*2*1 = 384 different possibilities!

  • Math -

    There are 384 possibilities.

  • Math -

    uhhhhhhhh are you sure cause that doesn't sound posible. especialy if the couples have to sit side by side

  • Math -

    i know u included the couples sitting side by side but still

  • Math -

    Yes, if the couples were not required to sit next to each other then the number of possibilities would be (8*7*6*5*4*3*2*1) = 40,320. I've taken Statistics at Georgia Tech and this was the fun part!!

  • Math -

    got it. Thanks so much.

  • Math -

    there are six ways each of them can sit next to each of them sit. five to sit next to them. six times six = thirtysix
    five times five = 30 add them together you get 66

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Data Management

    At a banquet, 4 coupes are sitting along one side of a table with men & women alternating. a) how many seating arrangements are possible for these eight people?
  2. maths

    All the students in a school are made to stand in rows so as to form an equilateral triangle. The first row consists of one student, the second row 2 students, third row 3 students and so on. Had there been 90 more students, the total …
  3. math 12

    Find the number of seating arrangements of eight basketball players on a bench if either the one centre or both of the two forwards must sit at the end where the coach always sits.
  4. 9th grade math

    the triange is 31cm, side 1 and side 2 have equal lenghts, while side 3 is one centimeter shorter than twice then length of side 1, how long is each side?
  5. Pre-Cal

    Four couples have reserved seats in a row for a concert. How many ways can they be seated if the two members of each couple wish to sit together?
  6. math

    Consider an equilateral triangle with points located at each vertex and at each midpoint of a side. (See picture.) This problem uses the set of numbers {1, 2, 3, 4, 5, 6}. Place one number at each point. Call the sum of the three numbers …
  7. stats

    Four married couples have bought eight seats in a row for a musical play. In how many ways can they be seated if each couple is to sit together with the wife to the left of her husband?
  8. Math/Precal

    There are 12 students to be seated in a row of 12 chairs, paul and martha have broken up and will not sit together. How many different seating arrangements are possible?
  9. Math

    There are 12 students to be seated in a row of 12 chairs. Paul and Martha have broken up and will not sit together. How many different seating arrangements are possible?
  10. Math

    A hockey team is lining up in a row for a group photo there team has one goalie four defence and seven forwards the photographer wants the defence on one side of the goalie and the forwards on the other side how many ways can the team …

More Similar Questions