algebra help mrs. Sue

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Mrs.Sue my homework from yesterday i had wrong instructions i needed to find the mean median and mode. not the outlier an affect. my teacher switched the assignment
can you check my answers i have to find the mean, median and mode
1)
8 12 6 9 5
mean: 8
median : 8
mode : no mode

2) 3.4 0.53 1.3 2.9 1.47 0.24
mean: 1.64
median : 1.385
mode: no mode

3) -6 3 -2 6 7 -3 -5 8
mean : 1
median : 1 (? not sure on that)
mode : no mode

4) -17 32 -9 0 52 12 -14

mean: 8
median: 0
mode no mode

5) 75 72 46 77 70 80 68
mean: 70.25
median : 73
mode: no mode

6) -15 -12 -19 0 -20 -14
mean: 13.33
median : 14.5
mode: no mode

7) 5.3 5.1 5.2 14.7 5.8 5.9 5.4
mean: 6.77
median: 5.4
mode: no mode

8) 4 -1 -16 2 0 -3 6 -2
mean: 1.25
median: -1
mode: no mode

• algebra help Ms. Sue -

Please note that my name is Ms. Sue.

Your first two answers are right. However, without commas or a list, I can't really determine what your problems are.

It looks as though you have the right idea for solving these mean and median problems.

• algebra help mrs. Sue -

quetion 3)
-6
3
-2
6
7
-3
-5
8
question 4)
-17
32
-9
0
52
12
-4

question 5)
75
72
74
46
77
70
80
68

question 6
-15
-12
-19
0
-20
-14

question 7

5.3
5.1
5.2
14.7
5.8
5.9
5.4

QUETION 8
-16
-3
-2
-1
0
2
4
6

• algebra help mrs. Sue -

3)there are two medians -2 and 3 , so the median is the mean of -2and 3, that's (-2+3)/2 = 1/2=0.5
mode is an average , you can not say there is no average for a given data , so here any value can be taken as the mode
8) the mean = -1.25
median = mean of -1 and 0= -1/2= -0.5
5) median = 72
and some more mistake are there i hope MARKO you will be able to correct it
bye :)

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