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calculus

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how to find all real zeros of "4x^5+8x^4-15x^3-23x^2+11x+15

  • calculus -

    Since there is no general method to solve a quintic equation, we must assume that there is some low-hanging fruit, root-wise.

    y(1) = 0, so
    y = (x-1)(4x^4 + 12x^3 - 3x^2 - 26x - 15)

    Try 1 again: no joy
    Try -1. Yay and we have
    y = (x-1)(x+1)(4x^3 + 8x^2 - 11x - 15)

    Try -1 again: yay
    y = (x-1)(x+1)(x+1)(4x^2 + 4x - 15)

    y = (x-1)(x+1)(x+1)(2x-3)(2x+5)

    I assume you can find the roots at this point...

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