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a rectangular plot of ground having dimensions 46 feet by 30 feet is surrounded by a walk of uniform width. If the area of the walk is 240 ftˆ2, what is its width?

  • math -

    area w/o walk: 46*30 = 1380
    area w/walk (46+2w)(30+2w)

    So, we have

    (46+2w)(30+2w) - 1380 = 240
    4w^2 + 152w + 1380 - 1380 = 240
    4w^2 + 152w - 240 = 0
    w^2 + 38w - 60 = 0
    w = -19 + sqrt(421) = 1.5

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