calc
posted by terra .
find derivative using limit definition:
f(x) = x  sqrt(x)
so f'(x) =
lim
h>0 [f(x+h)  f(x)]/h
but I keep trying to solve by multiplying by the conjugate but I can't figure it out..there's nothing that can be cancelled or anything and I can't get the derivative
sorry this is a repost, but i messed up my other one and i really need help on this

calc 
Steve
The key to this is the binomial theorem:
(x+h)^n = x^n + n*x^(n1)*h + n(n1)/2 * x^(n2) * h^2 + ...
So, we find ourselves with
(h + sqrt(x)  sqrt(x+h))/h
= (h + x^(1/2)  (x^(1/2) + 1/2 * x^(1/2)*h + <higher powers of h>)/h
= 1  1/2 * x^(1/2)
(all terms with h go to zero)
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