# specific heat capacity

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How much heat would be required to heat 1 gram of pure liquid water from 10C to 20C?

How would i approach this problem?

• specific heat capacity -

figured it out.

• specific heat capacity -

20-10=10*1*4.18=41.8 joul/1 gm
1 cal = 4.18 joul
s.h.w=1 cal/gm

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