algebra

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a purse contains 26 coins, some of which are dimes and the rest are nickels. Altogether, the coins are worth more than \$2.10. At least how many dimes are in the purse?

• algebra -

Let x = # dimes and y = # of nickels.

x + y = 26
y = 26-x

10x + 5y = 210

Substitute 26-x for y in second equation and solve for x. Insert that value into the first equation and solve for y. Check by inserting both values into the second equation.

• algebra -

at least 17

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