What volume of each of the following acids will react completely with 25.50 mL of 0.700 M NaOH?
(a) 0.100 M HCl
(b) 0.150 M HNO3
(c) 0.200 M HC2H3O2
See your last post and the sample stoichiometry problem.
To find the volume of each acid that will react completely with 25.50 mL of 0.700 M NaOH, you need to use the concept of stoichiometry and the balanced chemical equations for the reactions.
Let's go through each acid one by one:
(a) 0.100 M HCl:
The balanced chemical equation for the reaction between HCl and NaOH is:
HCl + NaOH -> NaCl + H2O
By looking at the equation, we can see that the stoichiometric coefficient of HCl is 1. This means that 1 mole of HCl reacts with 1 mole of NaOH.
To determine the volume of HCl required to react with 25.50 mL of 0.700 M NaOH, you can use the following steps:
1. Calculate the number of moles of NaOH in 25.50 mL:
Moles of NaOH = (0.700 mol/L) x (0.02550 L) = 0.01785 mol
2. Since the stoichiometric coefficient of HCl is 1, the number of moles of HCl required to react completely with NaOH is also 0.01785 mol.
3. Calculate the volume of 0.100 M HCl required to contain 0.01785 mol:
Volume of HCl = (0.01785 mol) / (0.100 mol/L) = 0.1785 L
Therefore, the volume of 0.100 M HCl that will react completely with 25.50 mL of 0.700 M NaOH is 0.1785 L or 178.5 mL.
(b) 0.150 M HNO3:
Following the same steps as above, you can calculate the volume of 0.150 M HNO3 required to react completely with 25.50 mL of 0.700 M NaOH:
1. Calculate the number of moles of NaOH in 25.50 mL:
Moles of NaOH = (0.700 mol/L) x (0.02550 L) = 0.01785 mol
2. Since the stoichiometric coefficient of HNO3 is also 1, the number of moles of HNO3 required to react completely with NaOH is 0.01785 mol.
3. Calculate the volume of 0.150 M HNO3 required to contain 0.01785 mol:
Volume of HNO3 = (0.01785 mol) / (0.150 mol/L) = 0.119 L
Therefore, the volume of 0.150 M HNO3 that will react completely with 25.50 mL of 0.700 M NaOH is 0.119 L or 119 mL.
(c) 0.200 M HC2H3O2:
Similarly, you can calculate the volume of 0.200 M HC2H3O2 required to react completely with 25.50 mL of 0.700 M NaOH:
1. Calculate the number of moles of NaOH in 25.50 mL:
Moles of NaOH = (0.700 mol/L) x (0.02550 L) = 0.01785 mol
2. Since the stoichiometric coefficient of HC2H3O2 is also 1, the number of moles of HC2H3O2 required to react completely with NaOH is 0.01785 mol.
3. Calculate the volume of 0.200 M HC2H3O2 required to contain 0.01785 mol:
Volume of HC2H3O2 = (0.01785 mol) / (0.200 mol/L) = 0.08925 L
Therefore, the volume of 0.200 M HC2H3O2 that will react completely with 25.50 mL of 0.700 M NaOH is 0.08925 L or 89.25 mL.