posted by destinee .
A quarterback throws the football to a sta-
tionary receiver who is 26 m down the field.
The football is thrown at an initial angle of
36.5 to the ground.
The acceleration of gravity is 9.81 m/s2 .
a) At what initial speed must the quarter-
back throw the ball for it to reach the receiver?
Answer in units of m/s
range = 26 m = (Vo^2/g)*sin(2*36.5)
26 = (Vo^2/9.81)*sin73
Vo^2 = 266.7 m^2/s^2
Vo = ?