Algebra II
posted by Lois .
The length of a rectangle is twice its with. The are is 128yd^2. Find the length and the Width

L = Length
W = With
A = Area
L = 2 W
A = L * W
A = 2 W * W
A = 2 W ^ 2
128 = 2 W ^ 2 Divide both sides with 2
64 = W ^ 2
W = sqrt ( 64 )
W = 8 yd
L = 2 W = 2 * 8 = 16 yd
A = L * W = 8 * 16 = 128 yd ^ 2