Algebra
posted by Martha .
Hello, I have been trying a few ways to do this problem and am not having success.
The sum of four consecutive odd integers is 212. Write an expression for the second, third and fourth odd integers. Use these expressions to write, and solve an equation to find the four integers.
So, I tried first:
n + n+2 + n+4 + n+6 = 212
my answer 56, which is even so no good.
then i tried
2n+1 + 2n+3 + 2n+5 + 2n+7 = 212
my answer came out to 28.5
which is a decimal, so no good.
Can you please help?
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