Algebra

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Find the vertex and the axis of symmetry for the parabola with the given equation y=5x2-30+47....

  • Algebra -

    I will assume you have a typo, with the first term 5x^2 and that the second term is -30x

    the x of the vertex = -b/(2a) = 30/(10) = 3
    sub in x=3
    y = 5(9) - 30(3) + 47 = 2

    vertex (3,2)
    axis of symmetry : x = 3

  • Algebra -

    Thanks, I was getting something like 9
    now I see what I did wrong.

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