Algebra
posted by Al .
solve equations by elimination
2x6y=3 (1)
4x+9y=1 (2)

Algebra 
Anonymous
Multiply first equation with 2
 4 x + 12 y = 6
Note that, if you add down, the y's will cancel out.
 4 x + 12 y =  6
4 x + 9 y =  1
(  4 x + 4 x ) + ( 12 y + 9 y ) = 6 + ( 1 )
0 + 21 y = 6  1
21 y =  7 Diwide both sides with 21
y =  7 / 21
( Remark: 7 / 21 = 1 / 3 )
y=  1 / 3
First equation:
2 x  6 y = 3
2 x  6 * (  1 / 3 ) = 3
2 x + 6 / 3 = 3
2 x + 2 = 3
2 x = 3  2
2 x = 1 Divide both sides with 2
x = 1 / 2
x = 1 / 2 , y=  1 / 3 
Algebra 
KK
Thank You
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