Algebra 1
posted by Loren .
Using substitution, solve this equation..
3x  5y = 11
x  3y = 1

Equation 2 looks like it would be easy to solve for x, so we take it and isolate x:
x  3y = 1
x = 1 + 3 y
Now we can use this result and substitute x = 1 + 3 y in for x in equation 1:
3x  5y = 11
3 * ( 1 + 3 y )  5 y = 11
3 + 9 y  5 y = 11
3 + 4 y = 11
4 y = 11  3
4 y = 8 Divide both sides with 4
y = 2
x = 1 + 3 y
x = 1 + 3 * 2
x = 1 + 6
x = 7