PreCalc/Trig
posted by Sheila
Please helpI'm stuck really bad
What are the roots of the equation x^2  4x + 3 = 0
I think I was suppose to use b^2  4ac
so it would be 4  (4)*1*3 = 12 so the roots would be 12 and 12
Thank you for any help you can provide

Sheila
x^2 4x + 3 = 0
x^2  4x = 3
x^2 +2(2)x + 2^2 = 3 = 2^2
x^2 + 4x + 4 = 1
(x + 2)^2 = 1
qrt (x+2)^2 = sqrt 1
x+2 = plus or minus 1
therefore x=1
x=3 roots are 1 and 3
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