posted by terra .
Simplify by referring to the appropriate triangle or trigonometric identity:
sketch a right-angled triangle with some angle Ø
, label the opposite side x and the adjacent side 1
(this way tanØ = x/1 , and Ø = arctan(x/1)
the hypotenuse would be √(x^2 + 1)
cosØ = 1/√(x^2+1)