# algebra

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A jogger leaves home and runs at a constant speed of 4 miles per hour. Nine minutes later, a bicyclist follows along the same route at a constant speed of 15 miles per hour. Find the bicyclist's travel time needed to catch the jogger.

• algebra -

9 minutes = .15 hour

they both went the same distance.

bikers time ---- t hrs
jogger's time -- t+.15

15t = 4(t+.15)
15t = 4t + .6
11t = .6
t = .0545 hrs or 3.2727 minutes or 3 min and 16.4 seconds

• algebra -

3/11 minutes

• algebra -

Junior drove 55.6 miles then he drove 42 1/5 miles. How many miles did he drove in all??

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