Calculus

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Infinite series question.

an=2+(0.99)^n

Converge or Diverge?

• Calculus -

look at .99^n

.99^5 = .95099049.....
.99^250 = .08105...

as n ---> ∞ the value of .99^n approaches zero
so you are left with
2 + 0

so it converges to the value of 2

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