Calculus
posted by Mike .
Infinite series question.
an=2+(0.99)^n
Converge or Diverge?

look at .99^n
.99^5 = .95099049.....
.99^250 = .08105...
as n > ∞ the value of .99^n approaches zero
so you are left with
2 + 0
so it converges to the value of 2