Calculus
posted by Mike .
Infinite series question.
an=2+(0.99)^n
Converge or Diverge?

look at .99^n
.99^5 = .95099049.....
.99^250 = .08105...
as n > ∞ the value of .99^n approaches zero
so you are left with
2 + 0
so it converges to the value of 2
Respond to this Question
Similar Questions

algebra
does the infinite geometric series diverge or converge? 
calculus
Does the series from 0 to infinity of [1/square root of (n+4)] x cos(n x pi) converge or diverge? 
calculus
The sum from n=1 to infinity of cos(npi/3)/n! Does this absolutely converge, conditionally converge, or diverge? 
Calculus
does infinite power series 1/n diverge? (i think so, because it is just the negative of the harmonic series)...? 
Calculus 2
Does Series n=1 to infinity 1/2n+1 converge or diverge? 
Calculus 2
n=1 series to infinity (5^n)/n^3 does it absolutely converge, diverge or conditionally converge. Would I be applying the ratio test? 
Calculus II
Does 3/(2^(n) +1) diverge or converge in an infinite sum? 
Calculus
does the series 1/(n^2+n) converge or diverge? 
Algebra 2
I need steps on how to complete this please i am so confused and lost. :( Consider the infinite geometric series x e n=1 4(1/3) n1. In this image, the lower limit of the summation notation is "n=1". a. Write the first four terms … 
Calculus
Does the series converge? diverge? Use the Root test ((1/n)(1/n^2))^n