Physics
posted by Anon14 .
A car starts from the origin and is driven 1.72 km south, then 3.11 km in a direction 58° north of east. Relative to the origin, what is the car's final location? Express your answer in terms of an angle (in degree)
and a distance.

X = hor. = 3.11cos58 = 1.65km.
Y=ver. = 3.11sin58 + (1.72) = 0.92km.
tanA = Y / X = 0.92 / 1.65 = 0.5560,
A = 29.1 deg.
R = X / cosA = 1.65 / cos29.1 = 1.89km
@ 29.1 deg. North of East.
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