# algebra

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write the slope-intercept equation for the line that passes through (-8,-11) and is perpendicular to -2x-7y=-14

• algebra -

Lines perpendicular to:
-2x-7y=-14
would have the form:
-7x+2y=k
where k is a constant to be determined using the point (-8,-11).
Substitute x=-8, y=-11, we get
-7(-8)+2(-11)=k
=>
k=34
The line is therefore
-7x+2y=34

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