Calculus

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find tha value of f(x)=x3 where f(x+h)-f(x)/h

so far I got 3x2+3hx+h2/h and got stuck from here.

  • Calculus -

    Perhaps you have
    f(x) = x^3 (do you have a typo?)
    and you want f'(x) ?

    f(x+h) = (x+h)^3 = x^3 + 3 x^2h + 3 xh^2 + h^3

    subtract x^3
    f(x+h) -f(x) = 3 x^2h + 3 xh^2 + h^3

    divide by h

    3 x^2 + 3 xh + h^2

    let h -->0 for derivative
    f'(x) = 3 x^2 (the right answer)

  • Calculus -

    0.3 (3x + 9)>or equal to 1.2 -(x+2)

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