Math 116

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Create an equation of a nonlinear function and provide one positive and one negative value for x. Please show steps in how to solve it as well.

  • Math 116 -

    V(h,k)) = V(3,4), P(2,3).

    Y = a(x-h)^2 + k.

    P(2,3)
    Y = a(2-3)^2 + 4 = 3,
    a + 4 = 3,
    a = 3 - 4 = -1.

    Y = -1(x-3)^2 + 4, Vertex form.
    Y = -x^2 + 6x - 5. Standard form.

    -x^2 + 6x - 5 = 0,
    Solve using Quadratic Formula and get:
    X = 1, and X = 5.

    P1(-2,-21)
    P2(2,3).

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