Math 116
posted by University of Phoenix .
Create an equation of a nonlinear function and provide one positive and one negative value for x. Please show steps in how to solve it as well.

V(h,k)) = V(3,4), P(2,3).
Y = a(xh)^2 + k.
P(2,3)
Y = a(23)^2 + 4 = 3,
a + 4 = 3,
a = 3  4 = 1.
Y = 1(x3)^2 + 4, Vertex form.
Y = x^2 + 6x  5. Standard form.
x^2 + 6x  5 = 0,
Solve using Quadratic Formula and get:
X = 1, and X = 5.
P1(2,21)
P2(2,3).