physics
posted by armando .
a body moving with a uniform acceleration travels distances of 24m and 64m during the first two equal consecutive intervals of time each of duration 4s.determine the initial velocity and acceleration of moving body.

physics 
Damon
d = vi t + (1/2) a t^2
24 = vi (4) + (1/2) a (4)^2
88 = vi (8) + (1/2) a (8^2)

48 = 8 vi + 16 a
88 = 8 vi + 32 a
 subtract
40 = 16 a
a = 2.5 m/s^2
24 = 4 vi + 20
vi = 1 m/s
check my arithmetc 
physics 
Anonymous
a motor cyclist goes from station a to b at 40km/h and then returns from b to a 120km/h.calculate average speed,average velocity during the round trip

physics 
Anonymous
case 1:
from a to b velocity=40km/h=11.1m/s
let 11.1=a
case 2:
from b to a velocity=120kh/h=33.3m/s
let 33.3=b
avg.speed = ba/2
= 33.311.1/2
= 22/2
= 11m/s
avg. speed= 11m/s=40km/h
avg.velocity=0
because avg. velocity is total displacement/time.
now the cyclist travels from a to b then from b to a, back to its original
position. so the avg.velocity is zero.
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