math
posted by lisa .
an antique dealer visited three shops.she spent 25$ at the first shop.at the second shop she spent half of her remaining money .at the third shop she spent one third of her remaining money and had 60$ left.How much money did the dealer have originally?

Let x = original money
x  25  .5(x25)  [.5(x25)]/3 = 60
Solve for x. 
Original Amt. = $X.
1. Spent: $25.
Bal. = (X25).
2. Spent: (X25)/2.
Bal. = (X25)/2.
3. Spent: (1/3)(X25)/2 = (x25)/6.
Bal. = (X25)/2  (x25)/6,
Bal.=3(X25)/6  (X25)/6 = 2(X25)/6 =
(X25)/3.
Bal. = (X25)/3 = $60.
(X25)/3 = 60,
Multiply both sides by 3:
X  25 = 180,
X = 180 + 25 = $205. = Original Amt.