posted by Brit .
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region.
its not 8
I would take vertical slices, that is, integrate with respect to x
But after looking at the sketch, I realize that we have to find the intersection of the line 2x+2y=5 and 2y = 3√x
equating 3√x = 5-2x and squaring both sides I got
4x^2 - 29x + 25=0
x = 1 or x = 25/4
also if y=3, then 6=3√x ----> x = 4
so we need ∫(3 - 5/2 + x dx from 0 to 1 + ∫(3 - 3x^(1/2) ) dx from 1 to 4
Can you finish it?
-4?? that is incorrect..hmm, what am i doing wrong?