posted by Anonymous .
a conical tank is 15 feet deep and has an open top whose radius is 15 feet. Assume that starting at t = 0 water is added to the tank at a rate of pi ft^3/hr, and water evaporates from the tank at a rate proportional to the suface area with the constant of proportionality being 0.01. The tank is assumed to be empty at time t = 0. Let V and h represent the volume and depth of water in the tank.
solve the equation dh/dt = (1-0.01h^2)/h^2
Use separation of variables.
dt = h^2/(1-0.01h^2) dh
with h = 0 at t = 0