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What is the mass (in grams) of water that is produced when 100.0 grams of nitrogen monoxide is reacted with 75.0 grams of hydrogen according tho the following balanced eguation?

2NO + 5H2 = 2NH3 + 2H2O

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    As reactants, you have 100/30 = 3.33 moles of NO and 75/2 = 37.5 moles of H2. Clearly, NO is the limiting reactant and there is excess H2. Only 3.33 moles of H2O can be formed. Convert that to grams.

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