Calculus
posted by Josh .
put function in standard form
f(x)=4x^232x+9

There are many "standard forms". One of which is f(x)=a(xh)²+k
where (h,k) is the position of the vertex, and a is a constant.
This can be achieved by completing the square of
f(x)=4x^232x+9
=4(x²+8x9/4)
=4(x+4)²+4*4²+9/4
=4(x+4)²+265/4