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'm'gms of carbon reacts completely with 'n'gms of oxygen to produce carbon-dioxide.The mass of oxygen required to react with 'm'gms of carbon completely and produce carbon-monoxide is

  • science -

    Not entirely sure what is needed here

    Start from the equations

    C + O2 -> CO2

    1 mole + 1 mole -> 1 mole

    so

    m/12 + n/32 produces CO2

    so m/12=n/32 or

    32m=12n

    8m=3n

    n=8m/3

    C + 1/2O2 -> CO


    1 mole + 1/2 mole -> 1 mole

    m/12 n/32

    in this case

    m/12= 2n/32

    m/12=n/16

    mass of O2 required is

    16m/12 or 4m/3

    which is what we expect as half the number of moles i.e. half the mass i needed.

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