precal 2

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use the law of cosines to solve the triangle A=55 degree, c=10, b=3

  • precal 2 -

    a^2 = 10^2 + 3^2 - 2(10)(3)cos55°
    = 109 - 60cos55
    = 107.8528..
    a = 10.3852..

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