Calculus
posted by Carly .
Solve the separable differential equation: dy/dt=4y^6
and find the particular solution satisfying the initial condition y(0)=3
y(t)=?

Integral of dt = Integral of (1/4)y^6 dy
t = 1/(20 y^5) + C
0 = 1/20*243 +C
t = 1/(20 y^5) 1/4860
1/(20 y^5) = (1/4860)  t
y^5 = (1/20)/[(1/4860)  t]
= 243/[1 4860 t]
y = 3*[1 +4860 t]^(1/5)
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