posted by Chloe .
An object 0.600 cm tall is placed 16.5 cm to the left of the vertex of a concave mirror having a radius of curvature of 22.0 cm. (a) Draw a principle-ray diagram showing the formation of the image. (b) Calculate the position, size, orientation (erect or inverted), and nature (real or virtual) of the image.
We can't plot ray diagrams for you.
For the image location, use the standard equation, which you should know.
1/Di + 1/Do = 1/f
f = R/2 = 11 cm is the focal length
Do is the object distance
Di is the image distance
1/Di + 1/16.5 = 1/11
Di = 33 cm
Magnification = Di/Do = 2
It is a real inverted image.
F*** you! That wasn't the right answer!