math
posted by Anonymous .
A rectangular poster has an area of 190in(squared). The height of the poster is 1in. less than twice its width. Find the dimensions of the poster.

A = Area= 190 in^2
H = Hight
W = Width
H = 2W1
A = W*H
A = W*(2W1)
190 = 2W*W1*W
190 = 2W^2W
2W^2W190 = 0
The exact solutions of this equation are:
W=10
and
W= 19/2
Width can't be negative so:
W = 10 in
H = 2*W1
H = 2*101
H = 201
H = 19 in
W = 10 in
H = 19 in
A = W*H
A = 10*19
A = 190 in^2
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2W^2W190=0
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