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college algebra

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solve x^2e^x+9x^ex=0

  • college algebra -

    x^2e^x + 9xe^x = 0.
    Factor out e^x:
    e^x(x^2+9x) = 0,
    Divide both sids by e^x:
    x^2 + 9x = 0,
    x(x+9) = 0,
    x = 0.

    x + 9 = 0,
    x = -9.

    Solution Set: x = 0, and x =-9.

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