math
posted by rob .
find the eqt. of tangent to the curve y=x^2+2x10 @ the point where the curve cuts the yaxis.[ans:y=2x10]
how do i do this because they didn't give me the point...?

Yes, they did
It said, "where the curve cuts the yaxis", that is when x = 0
when x=0, y = 0 + 0  10 = 10
so your point is (0,10)
drwls answered this for you already, did you not read it?
http://www.jiskha.com/display.cgi?id=1311337279
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