posted by Naina .
A 8 V flashlight battery has an internal resistance of 1.7 Ω when new, and 8 Ω when old. Imagine this is a resistor in series with the battery mounted INSIDE the battery itself, which describes the chemical degradation of the battery with age. Calculate the voltage across a 14 Ω lamp (the load) when the battery is new. Express the answer with one decimal place.
Rt = 1.7 + 14 = 15.7 Ohms.
I = E/Rt = 8/15.7 = 0.51A,
V = IRl = 0.51 * 14 = 7.1 Volts across