Math: Parabola, Vertex
posted by John .
Find the vertex of the parabola associated with the quadratic function.
f(x)= 1/7x^2  2/11x + 1/121
(h,k)= What is the vertex of this quadratic function?

Hint: the xcoordinate of the vertex of a parabola y = ax^2 + bx + c is b/2a.

F(x) = x^2/7  2x/11 + 1/121,
h = b/2a = (2/11) / (2/7) = 7/11.
k = (7/11)^2/7 2(7/11)/11 + 1/121,
k = (49/121*1/7 + 14/11/11 + 1/121,
k = 7/121 +14/121 + 1/121 = 8/121.
V(h,k) = V(7/11,8/121). 
y^2+4y+2x=0