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Verify that each trigonometric equation is an identity tan^2+1/sec α =sec α

  • trig -

    I will assume you meant

    (tan^2 Ø + 1)/sec Ø = sec Ø

    by the Pythagorean identity
    tan^2Ø + 1 = sec^2 Ø , so ....

    LS = sec^2 Ø/secØ
    = secØ
    = RS

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